If A is 5 less than B, B is 2 more than C and C is 3 less than D. How much more or less is A than D.
A is 6 less than D
454
=432/932
To find out how much more or less A is than D, we need to determine the values of A and D first.
We are given the following information:
A is 5 less than B.
B is 2 more than C.
C is 3 less than D.
Let's assign variables to these quantities to make it easier to solve the problem. Let:
A = a
B = b
C = c
D = d
Using the given information, we can rewrite the equations as follows:
a = b - 5 (Equation 1)
b = c + 2 (Equation 2)
c = d - 3 (Equation 3)
We can now substitute the values of b and c from equations 2 and 3 into equation 1 to solve for a:
a = (c + 2) - 5
a = c - 3 (Equation 4)
Substituting the value of c from equation 3 into equation 4 gives:
a = (d - 3) - 3
a = d - 6 (Equation 5)
Thus, we have expressed A (a) in terms of D (d).
To determine how much more or less A is than D, we need to find the difference between these two values. Subtracting a from d:
Difference = d - a
Substituting the expression for a from equation 5 into the equation above:
Difference = d - (d - 6)
Difference = 6
Therefore, A (a) is 6 less than D (d).