HELPPPP!!!! A mixture is prepared using equal masses of the two volatile liquids benzene, C6H6, and ethanol, C2H5OH. What is the mole fraction of benzene in this mixture?
C6H6 has mol wt 78
C2H5OH has wt 46
so, since mass is equal, moles are in inverse proportion.
To find the mole fraction of benzene in the mixture, we need to know the number of moles of benzene and ethanol in the mixture.
The first step is to calculate the number of moles of benzene and ethanol using their masses and molar masses.
1. Find the molar mass of benzene (C6H6):
- The molar mass of carbon (C) = 12.01 g/mol
- The molar mass of hydrogen (H) = 1.01 g/mol
- Benzene consists of 6 carbon atoms and 6 hydrogen atoms.
- Molar mass of benzene = (6 * 12.01) + (6 * 1.01) = 78.11 g/mol
2. Find the molar mass of ethanol (C2H5OH):
- The molar mass of carbon (C) = 12.01 g/mol
- The molar mass of hydrogen (H) = 1.01 g/mol
- The molar mass of oxygen (O) = 16.00 g/mol
- Ethanol consists of 2 carbon atoms, 6 hydrogen atoms, and 1 oxygen atom.
- Molar mass of ethanol = (2 * 12.01) + (6 * 1.01) + 16.00 = 46.07 g/mol
3. Calculate the number of moles of benzene and ethanol:
- Mass of benzene = mass of ethanol (since they have equal masses)
- Moles of benzene = mass of benzene / molar mass of benzene
- Moles of ethanol = mass of ethanol / molar mass of ethanol
Once you have the number of moles of benzene and ethanol, you can calculate the mole fraction of benzene by dividing the moles of benzene by the total moles (sum of benzene and ethanol).
Mole fraction of benzene = Moles of benzene / (Moles of benzene + Moles of ethanol)
I hope this helps!