math
posted by Jen .
So I need to solve this differential equation
dy/dx = 1/(x+2)
so i solved it like this
dy = 1/(x+2)dx
then i took the integral of both sides
y= ⌠1/(x+2)dx
⌡
then performed a u sub
u = x+2
du = 1dx
y = ⌠du/u
⌡
y = ln abs(u)+c
y = ln abs(x+2)+c
but the sanswer is supposed to be
y = ln abs ((x+2)/2) + c
Where did I mess up? and where did the 2 in the denominatior of the (x+2) come from?
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