Let x = 2 and y = 4. Find the value of the given capital letter.
N = x2 + 2xy + y2 + 1
does N= 37?
should be x^2 +2xy + y^2+1
I get
2^2 + 2(2)(4) + 4^2 + 1
= 4+16+16+1
= 37
You are correct
x^2 +2xy + y^2+1
4 + (2 * 2 * 4) + 16 + 1
4 + 16 + 16 + 1 = 37
You're right.
To find the value of N, we will substitute the given values of x and y into the equation and simplify.
Given:
x = 2
y = 4
N = x^2 + 2xy + y^2 + 1
Substituting the given values:
N = (2)^2 + 2(2)(4) + (4)^2 + 1
Simplifying:
N = 4 + 16 + 16 + 1
N = 37
Therefore, the value of N is indeed 37.