A woman weighs Fg= 600 N when standing on a stationary scale. Now, the woman is riding an elevator from the 1st floor to the 10th floor. As the elevator approaches the 10th floor, it decreases its upward speed from 7 m/s to 1 m/s in a time interval of 1 s. What is the average force exerted by the elevator floor on this woman during this 1 s interval? Use g=10 m/s2.

Question

A woman weighs Fg= 600 N when standing on a stationary scale. Now, the woman is riding an elevator from the 1st floor to the 10th floor. As the elevator approaches the 10th floor, it decreases its upward speed from 7 m/s to 1 m/s in a time interval of 1 s. What is the average force exerted by the elevator floor on this woman during this 1 s interval? Use g=10 m/s2.

a) 360N
b) 120N
c) 180N
d) 240N
e) 480N

Answer 1

240 for ur values

Answer 2

can someone elaborate on this problem, i have diferent values

Answer 3

a = (v - v0)/t = (1 m/s - 5 m/s)/(1 s) = -4 m/s^2

F = ma
N - mg = ma
N = m(a+g)
N = (w/g)(a+g)
N = w(a/g + 1)

N = (500 N)(-4 m/s^2 / 10 m/s^2 + 1) = 300 N

Answer 4

To find the average force exerted by the elevator floor on the woman during the 1-second interval, we need to consider the change in momentum of the woman.

First, let's find the final momentum of the woman just before the elevator slows down at the 10th floor.
Momentum (p) is given by the formula: p = mass (m) × velocity (v).
Since the mass is not given, but the weight is, we can use the weight (Fg) to find the mass.
Weight (Fg) is given by the formula: Fg = mass (m) × gravity (g).

Given that Fg = 600 N and g = 10 m/s², we can rearrange the formula to find the mass:
mass (m) = Fg / g = 600 N / 10 m/s² = 60 kg.

Next, let's calculate the initial and final momenta:
Initial momentum (p1) = m × v1 = 60 kg × 7 m/s = 420 kg·m/s.
Final momentum (p2) = m × v2 = 60 kg × 1 m/s = 60 kg·m/s.

Now, we can find the change in momentum:
∆p = p2 - p1 = 60 kg·m/s - 420 kg·m/s = -360 kg·m/s.
The negative sign shows that the momentum decreased.

The change in momentum (∆p) is equal to the average force (Favg) multiplied by the time interval (∆t):
∆p = Favg × ∆t.

Rearranging the formula:
Favg = ∆p / ∆t = -360 kg·m/s / 1 s = -360 N.

The average force exerted by the elevator floor on the woman during this 1-second interval is -360 N.

However, since force should be a positive value, we take the magnitude of the force:
Magnitude of the force = |Favg| = |-360 N| = 360 N.

So, the average force exerted by the elevator floor on the woman during this 1-second interval is 360 N. Therefore, the correct answer is option a) 360N.