Write the balanced equation for the hydration of CuSO4. Indicate the physical states using the abbreviations (s), (l), or (g) for solid, liquid, or gas, respectively. Use (aq) to indicate the aqueous phase. Indicate appropriate charges on negative and positive ions if they are formed.

I don't know if you want just the hydration or something else. The following is not just a hydration step.

CuSO4(s) + 4H2O(l) ==> Cu(H2O)4^++(aq) + SO4^=(aq)

The simpler straight hydration step is (and I write H2O as a gas meaning vapor).
CuSO4(s) + 5H2O(g) ==> CuSO4.5H2O(s)

To write the balanced equation for the hydration of CuSO4, we first need to understand the reaction and the compounds involved.

CuSO4 is the chemical formula for copper(II) sulfate, which is a salt containing a copper ion (Cu2+) and a sulfate ion (SO42-). When copper(II) sulfate is hydrated, it absorbs water molecules to form a hydrated copper(II) sulfate compound.

Here's how you can write the balanced equation for the hydration of CuSO4:

Step 1: Write the chemical formula of the hydrated copper(II) sulfate.

The general formula for hydrated copper(II) sulfate is CuSO4 · xH2O, where x represents the number of water molecules attached to each copper(II) sulfate formula unit.

Step 2: Determine the number of water molecules in the hydrated compound.

In this case, when copper(II) sulfate is hydrated, it can bind to 5 water molecules. Therefore, the formula for the hydrated copper(II) sulfate would be CuSO4 · 5H2O.

Step 3: Write the balanced equation.

CuSO4 (s) + 5H2O (l) ⟶ CuSO4 · 5H2O (s)

In this balanced equation, (s) represents solid, (l) represents liquid, and in this case, both the reactant and product are solids.

Remember, charges are not indicated for solid compounds. The charges will only be necessary if you are working with ionic compounds in aqueous solutions.

I hope this helps! Let me know if you have any further questions.

The balanced equation for the hydration of CuSO4 is:

CuSO4(s) + 5H2O(l) → CuSO4 • 5H2O(aq)

In this equation, copper sulfate (CuSO4) in its solid state reacts with water (H2O) in its liquid state to form a hydrated form of copper sulfate, commonly known as pentahydrate. The pentahydrate form is represented by CuSO4 • 5H2O(aq), where (aq) indicates the aqueous phase and the · symbolizes the attachment of water molecules to the copper sulfate compound.

Note that there is no change in charge for the ions in this reaction, so charges are not explicitly indicated.