The length of a rectangle is 1 meter more than 5 times it's width. The perimeter of the rectangle is 98 meters. Find the length and width of the rectangle.
w + (5w+1) = 49
now get w and figure length.
So is it 5w^2+1w=49? I'm still confused.
who told you to multiply? We don't care about the area. Just add them up. The width plus the length (5w+1) = 1/2 the perimeter
w+5w+1 = 49
6w = 48
w = 8
so, length = 41
My bad. I forgot that we were adding, not multiplying. Thank you
Two airplanes leave St. Louis at the same time and fly in opposite directions. If one travels at 500 kilometers per hour, and the other at 600 kilometers per hour, how long will it take for them to be 1925 kilometers apart?
The perimeter of a rectangle is 180 meters. The length is 50 meters greater than the width. Find the dimensions of the rectangle.
To find the length and width of the rectangle, we can set up an equation using the given information.
Let's say the width of the rectangle is 'w' meters.
According to the given information, the length of the rectangle is 1 meter more than 5 times its width, so the length can be expressed as (5w + 1) meters.
The perimeter of a rectangle is given by the formula: Perimeter = 2(length + width)
In this case, the perimeter is 98 meters, so we can set up the equation:
98 = 2((5w + 1) + w)
Now, let's solve this equation to find the value of 'w':
98 = 2(6w + 1)
98 = 12w + 2
12w = 98 - 2
12w = 96
w = 96/12
w = 8
Now that we have the value of 'w', we can find the value of the length:
Length = 5w + 1
Length = 5(8) + 1
Length = 40 + 1
Length = 41
Therefore, the width of the rectangle is 8 meters and the length is 41 meters.