find the foci of 9x^2-25y^2=225 I get this far a^2=5 and B^2=3 AND I KNOW I HAVE TO USE THE formula c^2=a^2-b^2 i don't know what to do now if add it i get c^2=34 please help show the step thanks
9x^2 - 25y^2 = 225
divide by 225
x^2/25 - y^2/9 = 1
a^2= 25 , and b^2 = 9 , (you had a^2 = 5 and b^2 = 3)
ok, so c^2 = a^2 - b^2 = 25 - 9 = 34
c = ± √34
the foci are (√34,0) and (-√34 , 0)