How many milliliters of a 0.5 molar HCl solution are needed to react completely with 15 grams of zinc according to the following equation?

? HCl+? Zn→? ZnCl2 +? H2 Answer in units of mL

To determine the number of milliliters of a 0.5 M HCl solution needed to react completely with 15 grams of zinc, we need to use the stoichiometry of the balanced chemical equation.

The balanced equation for the reaction between HCl and zinc (Zn) is:

2HCl + Zn → ZnCl2 + H2

From the balanced equation, we can see that 2 moles of HCl react with 1 mole of zinc (Zn).

First, we need to calculate the moles of zinc in 15 grams of zinc.

The molar mass of zinc (Zn) is 65.38 g/mol.
Number of moles of zinc = mass of zinc / molar mass of zinc
Number of moles of zinc = 15 g / 65.38 g/mol = 0.229 moles

Since 2 moles of HCl react with 1 mole of zinc, we can determine the moles of HCl required using the stoichiometric ratio.

Number of moles of HCl = 2 * Number of moles of zinc
Number of moles of HCl = 2 * 0.229 moles = 0.458 moles

Now, we can use the molarity of the HCl solution to calculate the volume.

Molarity (M) = moles of solute / volume of solution (in liters)

We can rearrange the equation to solve for the volume of the solution:

Volume of solution (in liters) = moles of solute / molarity

Volume of solution (in liters) = 0.458 moles / 0.5 M = 0.916 L

Finally, we need to convert the volume from liters to milliliters:

Volume of solution (in mL) = Volume of solution (in L) * 1000 mL/L
Volume of solution (in mL) = 0.916 L * 1000 mL/L = 916 mL

Therefore, you would need approximately 916 mL of a 0.5 M HCl solution to react completely with 15 grams of zinc.

To find the answer to this question, we need to use the stoichiometry of the balanced chemical equation and the molar mass of the substance involved. Let's break down the process step by step:

Step 1: Write the balanced chemical equation.
The given equation is:
HCl + Zn → ZnCl2 + H2

Step 2: Calculate the molar mass of zinc (Zn).
The molar mass of zinc (Zn) can be found on the periodic table, which is approximately 65.38 grams per mole.

Step 3: Calculate the number of moles of zinc (Zn) using the given mass.
To find the number of moles, use the formula:
moles = mass / molar mass

moles of Zn = 15 g / 65.38 g/mol

Step 4: Use the stoichiometry of the balanced equation to determine the ratio between moles of HCl and moles of Zn.
From the balanced equation:
1 mole of HCl reacts with 1 mole of Zn

Step 5: Convert the moles of Zn to moles of HCl.
Since the stoichiometric ratio is 1:1, the number of moles of HCl is the same as the number of moles of Zn.

moles of HCl = moles of Zn = 15 g / 65.38 g/mol

Step 6: Use the molarity (0.5 M) of the HCl solution to find the volume in liters.
The molarity of HCl (M) is defined as moles of solute per liter of solution.

volume of HCl (in L) = moles of HCl / Molarity

Step 7: Convert liters to milliliters.
Since 1 L = 1000 mL, multiply the volume in liters by 1000 to get the volume in milliliters.

volume of HCl (in mL) = volume of HCl (in L) * 1000

Now, let's put this all together to find the answer:

moles of HCl = 15 g / 65.38 g/mol
moles of HCl = 0.229 mol

volume of HCl (in L) = 0.229 mol / 0.5 M
volume of HCl (in L) = 0.458 L

volume of HCl (in mL) = 0.458 L * 1000
volume of HCl (in mL) = 458 mL

Therefore, 458 milliliters of a 0.5 molar HCl solution are needed to react completely with 15 grams of zinc.