Writing equations in point-slope form:
m:3, p:(-1, -2)
y = mx + b
-2 = (3)(-1) + b
-2 = -3 + b
-2+3 = 3-3 + b
b= 1
y = 3x + 1
YOUR STUPID
7/3->7-3=4->4/3->1 4/3->4-3=1->1 1/3->2 1/3
SORRY
To write the equation of a line in point-slope form, you need two pieces of information: the slope of the line (m) and a point that lies on the line (p). In this case, you have the slope (m = 3) and a point (p = (-1, -2)).
The point-slope form of an equation is given by y - y1 = m(x - x1). To use this form, you plug in the values of the slope (m) and the coordinates of the point (x1, y1) into the equation.
Let's apply this to the given information.
m = 3 is the slope of the line.
p = (-1, -2) is a point on the line.
Using these values, we can replace m with 3 and substitute x1 = -1 and y1 = -2 into the equation.
y - (-2) = 3(x - (-1))
Simplifying further:
y + 2 = 3(x + 1)
This is the equation of the line in point-slope form, with slope (m = 3) and a point (p = (-1, -2)).