A stone is dropped from rest at the top of a

mine shaft. It takes 58 s for a stone to fall to
the bottom of a mine shaft.
How deep is the shaft? The acceleration of gravity is 9.8 m/s2 .

To find the depth of the shaft, we can use the equation of motion for an object in free fall:

d = (1/2)gt^2

Where:
d is the depth of the shaft
g is the acceleration due to gravity (9.8 m/s^2)
t is the time taken for the stone to fall (58 s)

Substituting the given values into the equation, we can calculate the depth of the shaft:

d = (1/2)(9.8 m/s^2)(58 s)^2

Calculating this expression:
d = (1/2)(9.8 m/s^2)(3364 s^2)
d = 16532.8 m^2/s^2

So, the depth of the shaft is approximately 16532.8 meters.

To determine the depth of the mine shaft, we can use the equation of motion for an object in free fall. The equation is:

d = (1/2) * g * t^2

Where:
d is the distance (depth) of the shaft,
g is the acceleration due to gravity (9.8 m/s^2),
t is the time it takes for the stone to fall (58 s).

Substituting these values into the equation, we get:

d = (1/2) * (9.8) * (58)^2

Now, let's calculate the result:

d = 0.5 * 9.8 * 3364
d = 16436.8 meters

Therefore, the depth of the mine shaft is approximately 16436.8 meters.

d = Vo*t + 0.5g*t^2

d = 0 + 4.9*58^2 = 16,484 m.