When a Superball bounces it is claimed that the height of any bounce is 90% of the height of the last bounce. If a Superball is dropped out of a second story window at the height of 200 feet. On which bounce would it bounce just one foot?

on 1st bounce goes up .9(200) ft

on 2nd bounce goes up .9(.9)(200) ft = .9^2 (200)
on 3rd bounce goes up .9^3 (200) ft

on nthe bounce goes up .9^n (200) ft
but that is supposed to be 1

.9^n (200) = 1
.9^n = 1/200 = .005
take log of both sides
n log .9 = log .005
n = log .005/log .9 = appr 50.3

check:
bounce #50 = 200(.9^50) = 1.03 ft
bounce #51 = 200(.9^51) = .93 ft

the 50th bounce is closes to 1 ft.

To determine on which bounce the Superball would bounce just one foot, we will use the given information that the height of each bounce is 90% of the previous bounce.

First, let's set up the equation to represent the height of each bounce:

Height of bounce = 0.9 * Previous bounce height

Let's start with the initial drop from the second-story window, which is 200 feet:

1st bounce: 0.9 * 200 = 180 feet

2nd bounce: 0.9 * 180 = 162 feet

3rd bounce: 0.9 * 162 = 145.8 feet

4th bounce: 0.9 * 145.8 = 131.22 feet

We continue this pattern until we find the bounce height of 1 foot.

5th bounce: 0.9 * 131.22 = 118.08 feet

6th bounce: 0.9 * 118.08 = 106.27 feet

7th bounce: 0.9 * 106.27 = 95.64 feet

8th bounce: 0.9 * 95.64 = 86.08 feet

9th bounce: 0.9 * 86.08 = 77.47 feet

10th bounce: 0.9 * 77.47 = 69.72 feet

11th bounce: 0.9 * 69.72 = 62.75 feet

12th bounce: 0.9 * 62.75 = 56.47 feet

13th bounce: 0.9 * 56.47 = 50.82 feet

14th bounce: 0.9 * 50.82 = 45.74 feet

15th bounce: 0.9 * 45.74 = 41.17 feet

16th bounce: 0.9 * 41.17 = 37.05 feet

17th bounce: 0.9 * 37.05 = 33.35 feet

18th bounce: 0.9 * 33.35 = 30.02 feet

19th bounce: 0.9 * 30.02 = 27.01 feet

20th bounce: 0.9 * 27.01 = 24.31 feet

21st bounce: 0.9 * 24.31 = 21.88 feet

22nd bounce: 0.9 * 21.88 = 19.69 feet

23rd bounce: 0.9 * 19.69 = 17.72 feet

24th bounce: 0.9 * 17.72 = 15.95 feet

25th bounce: 0.9 * 15.95 = 14.36 feet

26th bounce: 0.9 * 14.36 = 12.92 feet

27th bounce: 0.9 * 12.92 = 11.63 feet

28th bounce: 0.9 * 11.63 = 10.47 feet

29th bounce: 0.9 * 10.47 = 9.42 feet

30th bounce: 0.9 * 9.42 = 8.48 feet

The Superball would bounce just one foot on the 30th bounce.

To find the bounce on which the Superball would reach a height of one foot, we need to understand the pattern of decreasing heights with each bounce.

Given that the height of each bounce is 90% of the previous bounce, we can set up an equation to represent the relation between the bounce height and the number of bounces:

height_of_bounce = initial_height * (bounce_factor)^(number_of_bounces)

Let's work through the problem step by step:

1. The initial height of the Superball when dropped out of the second-story window is 200 feet. So, we have:
200 * (0.9)^n = 1

2. Simplifying the equation, we get:
(0.9)^n = 1/200

3. To solve for 'n', we need to take the logarithm of both sides. Let's use the logarithm base 0.9:
log(base 0.9) [(0.9)^n] = log(base 0.9) (1/200)

4. Applying the logarithmic property, the left side simplifies to 'n', resulting in:
n = log(base 0.9) (1/200)

Now, by plugging this equation into a calculator or using a logarithmic table, we can find the value of 'n' that satisfies the equation.