three times as many children as adults attended a concert on saturday. an adult ticket cost $7 and a child ticket cost $3. the theater collected a total of $6000. how many people bought tickets?
a = 3c
7a+3c = 6000
8a = 6000
a = 750
so, c=?
how did you get #8a, can you help me step by step please
oops. "three times as many children as adults " means c=3a
so, adding up the cost of the tickets, we have
7a+3c = 6000
7a+3(3a) = 6000
7a+9a = 6000
16a = 6000
a = 375
its 5th grade math, what other way can i show it
To solve this problem, we can set up a system of equations.
Let's assume that the number of adults attending the concert is A, and the number of children attending the concert is C.
According to the problem, "three times as many children as adults attended a concert on Saturday," so we have the equation:
C = 3A
The price of an adult ticket is $7, so the total amount collected from adults is:
7A
The price of a child ticket is $3, so the total amount collected from children is:
3C
The theater collected a total of $6000, so we have the equation:
7A + 3C = 6000
Now, we can substitute C = 3A into the second equation to solve for A:
7A + 3(3A) = 6000
7A + 9A = 6000
16A = 6000
A = 375
Now, substitute the value of A back into the first equation to find C:
C = 3A
C = 3(375)
C = 1125
Therefore, there were 375 adults and 1125 children who bought tickets to the concert, making a total of 375 + 1125 = 1500 people who bought tickets.