P2 +3H2=2ph3
How many grams of ph3 can be formed when 37.5 grams of p2 and 83 L of h2 gas are reacted at 1 atm and 273.25 K?
I really need a step by step of this problem. Thanks in advance!
This is a limiting reagent problem. Here is a step by step procedure for working a limiting reagent problem.
http://www.jiskha.com/science/chemistry/limiting_reagent_problem.html
dik
To solve this problem, we need to use stoichiometry and convert the given quantities to the desired quantity, which is grams of PH3.
Step 1: Write and balance the chemical equation:
P2 + 3H2 = 2PH3
Step 2: Convert the given quantity of P2 to moles:
Given mass of P2 = 37.5 grams
Molar mass of P2 = 30.97 g/mol
Number of moles of P2 = Given mass / Molar mass
Number of moles of P2 = 37.5 g / 30.97 g/mol
Step 3: Convert the given quantity of H2 to moles:
Given volume of H2 = 83 L
We need to convert the volume to moles using the ideal gas law.
PV = nRT
Where:
P = Pressure (in atm)
V = Volume (in liters)
n = number of moles
R = ideal gas constant (0.0821 L.atm/mol.K)
T = Temperature (in Kelvin)
Given:
P = 1 atm
V = 83 L
T = 273.25 K
Rearranging the ideal gas law equation to solve for n, we have:
n = PV / RT
Number of moles of H2 = (1 atm * 83 L) / (0.0821 L.atm/mol.K * 273.25 K)
Step 4: Determine the limiting reactant:
To determine the limiting reactant, we compare the moles of each reactant to the stoichiometric ratio in the balanced equation.
From the balanced equation:
1 mol P2 reacts with 3 mol H2 to form 2 mol PH3
By comparing the moles of P2 and H2, we can see which reactant limits the reaction.
Step 5: Calculate the maximum moles of PH3 that can be formed:
The limiting reactant will determine the number of moles of PH3 formed.
From the balanced equation:
1 mol P2 reacts with 2 mol PH3
Number of moles of PH3 = (Number of moles of P2) * (2 mol PH3 / 1 mol P2)
Step 6: Convert moles of PH3 to grams:
Given molar mass of PH3 = 33.99 g/mol
Mass of PH3 = Number of moles of PH3 * Molar mass of PH3
Step 7: Calculate the final answer:
Substitute the calculated values into the equation:
Mass of PH3 = (Number of moles of P2) * (2 mol PH3 / 1 mol P2) * (Molar mass of PH3)
Please note that in step 5, if the number of moles calculated for PH3 is greater than the moles calculated for P2, you need to recalculate the number of moles of PH3 based on the limiting reactant.
Follow these steps, and you will find the answer to the question on how many grams of PH3 can be formed when 37.5 grams of P2 and 83 L of H2 gas are reacted at 1 atm and 273.25 K.