how many grams of oxygen is needed to burn 500 grams of pentane?
Write and balance the equation.
Convert 500 g pentane to mols. mols = grams/molar mass
Using the coefficients in the balanced equation convert mols pentane to mols O2.
Now convert mols O2 to g O2. g = mols x molar mass.
To determine how many grams of oxygen is needed to burn 500 grams of pentane, we first need to determine the balanced chemical equation for the combustion of pentane.
The balanced equation for the combustion of pentane is:
C₅H₁₂ + 8O₂ ⟶ 5CO₂ + 6H₂O
From the balanced equation, we can see that for every 1 mole of pentane (C₅H₁₂), we need 8 moles of oxygen (O₂) to completely burn it.
The molar mass of pentane (C₅H₁₂) is approximately 72.15 g/mol.
To find the number of moles of pentane in 500 grams, we can use the equation:
moles = mass / molar mass
moles of pentane = 500 g / 72.15 g/mol = 6.92 moles
Since the ratio between pentane and oxygen is 1:8, we multiply the number of moles of pentane by 8 to find the number of moles of oxygen needed.
moles of oxygen = 6.92 moles pentane x 8 = 55.34 moles
Finally, we can find the mass of oxygen needed by multiplying the moles of oxygen by its molar mass, which is approximately 32 g/mol.
mass of oxygen = moles of oxygen x molar mass of oxygen
mass of oxygen = 55.34 moles x 32 g/mol = 1770.88 grams of oxygen
Therefore, approximately 1770.88 grams of oxygen is needed to burn 500 grams of pentane.
To determine how many grams of oxygen are needed to burn 500 grams of pentane, we first need to know the chemical equation for the combustion reaction. The balanced equation for the combustion of pentane is:
C5H12 + 8O2 -> 5CO2 + 6H2O
From the equation, we can see that for every one mole of pentane (C5H12), we need 8 moles of oxygen (O2) to completely burn it. The molar mass of pentane (C5H12) is approximately 72.15 g/mol. We can calculate the molar mass of oxygen (O2) as 16.00 g/mol.
Now, we can set up a proportion to determine the amount of oxygen required:
(500 g pentane) / (72.15 g/mol) = n / (8 mol of oxygen x 16.00 g/mol)
Simplifying the equation:
n = (500 g pentane) * (8 mol of oxygen x 16.00 g/mol) / (72.15 g/mol)
Calculating:
n ≈ 559.24 g
So, approximately 559.24 grams of oxygen are needed to burn 500 grams of pentane.