2.0 grams of Anhydrous sodium are mixed with 2.0 grams of calcium chloride dihydrate and 2.0 grams of calcium sulfate dihydrate are collected what is the percent yield. DO not round a number if used in a subsequent calculation
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If 2.0 Grams of anhydrous sodium sulfate are mixed with 2.0 grams of calcium chloride dihydrate and 2.0 grams of calcium sulfate dihydrate are collected, what is the percent yield?
To calculate the percent yield, we need to compare the actual yield (the amount of calcium sulfate dihydrate collected) to the theoretical yield (the maximum amount of calcium sulfate dihydrate that could be formed based on the reactants used).
First, we need to determine the balanced chemical equation for the reaction. From the given information, it seems that sodium reacts with calcium chloride dihydrate (CaCl2 · 2H2O) to produce calcium sulfate dihydrate (CaSO4 · 2H2O).
The balanced chemical equation for the reaction can be written as:
2 Na + CaCl2 · 2H2O → CaSO4 · 2H2O + 2 NaCl
From the equation, we can see that 2 moles of sodium react with 1 mole of calcium chloride dihydrate to produce 1 mole of calcium sulfate dihydrate.
Next, we need to calculate the theoretical yield of calcium sulfate dihydrate. To do this, we'll use the given mass of sodium (2.0 grams), assuming that all of it reacts completely.
The molar mass of sodium (Na) is approximately 23 g/mol. So, the number of moles of sodium used is:
moles of Na = (mass of Na) / (molar mass of Na) = 2.0 g / 23 g/mol ≈ 0.087 mol
Since 2 moles of sodium react with 1 mole of calcium sulfate dihydrate, the theoretical yield of calcium sulfate dihydrate can be calculated as follows:
theoretical yield = (moles of Na) × (molar mass of CaSO4 · 2H2O) / 2 ≈ (0.087 mol) × (172 g/mol) / 2 ≈ 7.47 g
Now, we can calculate the percent yield by using the actual yield (the collected amount of calcium sulfate dihydrate) and the theoretical yield.
Given that the actual yield of calcium sulfate dihydrate is 2.0 grams, we can calculate the percent yield as follows:
percent yield = (actual yield / theoretical yield) × 100 = (2.0 g / 7.47 g) × 100 ≈ 26.78%
So, the percent yield of calcium sulfate dihydrate in this reaction is approximately 26.78%.