For the diprotic weak acid H2A, Ka1 = 2.2 × 10-5 M and Ka2 = 7.8 × 10-7 M. What is the pH of a 0.0650 M solution of H2A? What are the equilibrium concentrations of H2A and A2– in this solution?

To find the pH of a solution of a diprotic acid like H2A, we need to consider the dissociation of both protons.

Let's denote the initial concentration of H2A as [H2A]₀. Since H2A is diprotic, we can assume that an equal amount of each proton is dissociated, so the equilibrium concentrations of H2A and the anion A2– can be represented as [H2A] and [A2–].

Step 1: Calculate the initial concentration of each species.
Since we have a 0.0650 M solution of H2A, the initial concentration of H2A is 0.0650 M. Since H2A dissociates in two steps, the initial concentration of [H2A]₀ is equal to [H2A].

Step 2: Calculate the concentrations of the species at equilibrium for each dissociation step.
For the first dissociation step: H2A ⇌ H⁺ + HA⁻

The equilibrium concentration [HA⁻] can be calculated using the equilibrium constant (Ka1) expression:
Ka1 = [H⁺][HA⁻] / [H2A]

Since H2A dissociates into one H⁺ ion and one HA⁻ ion, [H⁺] = [HA⁻]. Therefore, we can rewrite the expression as:
Ka1 = [H⁺]² / [H2A]

Since we know Ka1 and [H2A], we can rearrange the equation to solve for [H⁺]:
[H⁺]² = Ka1 * [H2A]
[H⁺] = sqrt(Ka1 * [H2A])

Similarly, for the second dissociation step: HA⁻ ⇌ H⁺ + A²⁻

Ka2 = [H⁺] [A²⁻] / [HA⁻]

Since [H⁺] = [A²⁻] in this step, we can simplify the equation to:
Ka2 = [H⁺]² / [HA⁻]
[H⁺] = sqrt(Ka2 * [HA⁻])

Step 3: Calculate the pH of the solution.
To find the pH, we use the equation:
pH = -log[H⁺]

Step 4: Calculate the equilibrium concentrations of H2A and A2–.
Since [H⁺] = [HA⁻], we can calculate the equilibrium concentration of [A²⁻] using the equation:
[A²⁻] = Ka2 * [HA⁻] / [H⁺]

By substituting the values we obtained from step two, we can calculate the equilibrium concentrations of H2A and A2–.

Remember to follow the significant figure rules and keep all the necessary decimal places in each calculation.

I hope this explanation helps you understand how to find the pH and equilibrium concentrations of H2A and A2– in a solution.

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