Post a New Question


posted by .

A 28.9 g sample of ethylene glycol, a car radiator coolant, loses 689 J of heat. What was the initial temperature of ethylene glycol if the final temperature is 32.5°C (c of ethylene glycol = 2.42 J/gK)?

  • chem -

    q = 689 = mass coolant x specific heat x (Tfinal-Tinitial)
    The only unknown is Ti

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

More Related Questions

Post a New Question