Algebra 1

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A man built a house costing 9 times as much as the lot on which it was built. If the lot cost $5, 000 less than 1/6 the cost of the house, what was the cost of each?

  • Algebra 1 -

    If the house cost h, then the lot is h/9

    h/6 - 5000 = h/9
    h = 90,000

  • Algebra 1 -

    Can you show me how to work it out

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