A daredevil decides to jump across a 15 m wide canyon on his motorcycle. The opposite side of the canyon is 3 m lower than the side the daredevil starts on. The daredevil drives his motorcycle off the cliff at a speed of 27 m/s.
How long does it take the daredevil to cross the canyon?
How far does the daredevil fall as he crosses the canyon?
To find the time it takes for the daredevil to cross the canyon, we can use the formula for time (t) with respect to distance (d) and velocity (v):
t = d / v
In this case, the distance (d) is 15 m (the width of the canyon), and the velocity (v) is 27 m/s (the speed at which the daredevil drives off the cliff). Plugging these values into the formula:
t = 15 m / 27 m/s
t ≈ 0.56 seconds
Therefore, it takes the daredevil approximately 0.56 seconds to cross the canyon.
Next, let's find how far the daredevil falls as he crosses the canyon. We can use the formula for falling distance (h) with respect to gravitational acceleration (g) and time (t):
h = 1/2 * g * t^2
In this case, the gravitational acceleration (g) is approximately 9.8 m/s^2 (assuming no air resistance). Plugging in the time we found earlier (t = 0.56 seconds):
h = 1/2 * 9.8 m/s^2 * (0.56 s)^2
h ≈ 1.56 meters
Therefore, the daredevil falls approximately 1.56 meters as he crosses the canyon.
1. d = 0.5g*t^2 = 3 m.
4.9t^2 = 3
t^2 = 0.6122
T = 0.782 s. To cross canyon.
2. 3 m.