Algebra parallel and perpendicular
posted by Tracy .
y=3/4x1 write equation for a line parallel to the given line passing through (4,0)

Algebra parallel and perpendicular 
Kuai
y = mx +b
0 = 3/4(4) + b
0 = 3 + b
b = 3
y = 3/4x + 3 
Algebra parallel and perpendicular 
Tracy
Thank you. can you explain the steps that you used.

Correction  Algebra parallel and perpendicular 
Reiny
Kuai is not correct, his line is NOT parallel with the given, since the slopes are different
easiest way:
if the new line is parallel to the given one, it must differ only in the constant
so new equation is
y = (3/4)x + b
sub in (4.0)
0 = (3/4)(4) + b
b = 3
y = (3/4)x  3
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