Algebra parallel and perpendicular

posted by Tracy

y=3/4x-1 write equation for a line parallel to the given line passing through (4,0)

  1. Kuai

    y = mx +b
    0 = -3/4(4) + b
    0 = -3 + b
    b = 3
    y = -3/4x + 3

  2. Tracy

    Thank you. can you explain the steps that you used.

  3. Reiny

    Kuai is not correct, his line is NOT parallel with the given, since the slopes are different

    easiest way:
    if the new line is parallel to the given one, it must differ only in the constant

    so new equation is
    y = (3/4)x + b
    sub in (4.0)
    0 = (3/4)(4) + b
    b = -3

    y = (3/4)x - 3

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