A solar cell with dimensions 12cm x 12cm is illuminated at standard test conditions. The cell presents the following external parameters:
Voc=0.8V,Isc=3A,Vmp=0.75V,Imp=2.5A
Calculate the fill factor in percentage [%]:
Calculate the efficiency (in %):
78.125 & 13
78.125 and 13
78 and 13
To calculate the fill factor, you need to know the open-circuit voltage (Voc), short-circuit current (Isc), maximum power voltage (Vmp), and maximum power current (Imp) of the solar cell. Fill factor is calculated using the equation:
Fill Factor (%) = (Vmp × Imp) / (Voc × Isc) × 100
Given the values for the external parameters of the solar cell, we can now calculate the fill factor:
Fill Factor (%) = (0.75V × 2.5A) / (0.8V × 3A) × 100
Simplifying the equation:
Fill Factor (%) = (1.875W) / (2.4W) × 100
Fill Factor (%) = 0.78125 × 100
Fill Factor (%) = 78.13%
Therefore, the fill factor is approximately 78.13%.
To calculate the efficiency of a solar cell, you need to know the maximum power output (Pmax) and the input power, which can be calculated using the formula:
Efficiency (%) = (Pmax / Pin) × 100
Where Pin is the input power or the incident power on the solar cell.
The maximum power output (Pmax) can be calculated as:
Pmax = Vmp × Imp
Given the values for Vmp and Imp, we can calculate Pmax:
Pmax = 0.75V × 2.5A
Pmax = 1.875W
Given that the incident power is not available in the problem statement, we cannot calculate the efficiency of the solar cell.