A rocket moves upward, starting from rest with an acceleration of 28.1 m/s2 for 4.76 s. It runs out of fuel at the end of the 4.76 s but does not stop. How high does it rise above the ground?
at time t > 4.76s, we have height
h = (1/2)(28.1)(4.76^2) + (28.1)(4.76)t - 4.9t^2
= 318.339 + 133.756t - 4.9t^2
This is a parabola with vertex at (13.65,1231.13)