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Mary applies a force of 77 N to push a box with an acceleration of 0.45 m/s2. When she increases the pushing force to 82 N, the box's acceleration changes to 0.74 m/s2. There is a constant friction force present between the floor and the box.
(a) What is the mass of the box?

  • physics -

    Fap-Fk = m*a

    Eq1: 77 - Fk = m*0.45
    Eq2: 82 - Fk = m*0.74
    Subtract Eq2 from Eq1:
    Diff. = -5 = -29m
    m = 0.172 kg.

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