Algebra 1
posted by Julia .
One longdistance telephone company offers a plan such that the first 20 minutes costs $.99 and each additional minute costs $.09. Solve an inequality to find the maximum amount of full minutes you can talk for $5.00.
At first I got: 5 is greater than or equal to .99+(1.8.09m)
But that's not right because i solved it and got a negative number and you can't talk for negative minutes

0.99 + 0.09x < 5.00
0.09x < 4.01
x < 4.01 / 0.09
x < 44.6 = 44
44 + 20 < 64 minutes