Calculate the mass of NaOH pellets required to prepare 1litre of 0.1Litre NaOH
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To calculate the mass of NaOH pellets required to prepare a given concentration of NaOH solution, you need to know the concentration of the solution and the volume you want to prepare.
In this case, you want to prepare 1 liter of a 0.1 M NaOH solution.
"Molarity" (M) is a unit that represents the concentration of a solute in a solution. It is defined as the number of moles of solute per liter of solution.
To calculate the mass of NaOH, you need to use the equation:
Mass (g) = Concentration (M) x Volume (L) x Molecular Weight (g/mol)
First, let's calculate the number of moles of NaOH needed:
Number of moles = Concentration (M) x Volume (L)
Number of moles = 0.1 M x 1 L = 0.1 moles
The molecular weight of NaOH is 22.99 g/mol (sodium: 22.99 g/mol + oxygen: 16.00 g/mol + hydrogen: 1.01 g/mol).
Finally, we can calculate the mass of NaOH:
Mass (g) = 0.1 moles x 22.99 g/mol = 2.299 g
Therefore, you would need approximately 2.299 grams of NaOH pellets to prepare 1 liter of a 0.1 M NaOH solution.