Calculate the mass of NaOH pellets required to prepare 1litre of 0.1Litre NaOH
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To calculate the mass of NaOH pellets required, we need to know the molar mass of NaOH (sodium hydroxide) and the desired concentration.
The molar mass of NaOH is:
Na = 22.9898 g/mol
O = 15.9994 g/mol
H = 1.0079 g/mol
Adding up the atomic masses:
Na + O + H = 22.9898 + 15.9994 + 1.0079 = 40.9971 g/mol
To find the mass of NaOH pellets needed for 1 liter (1000 mL) of 0.1 M NaOH solution, we can use the equation:
moles = volume × concentration
First, let's convert the volume from liters to milliliters:
1 liter = 1000 milliliters
Now, substituting the given values into the equation:
moles = 1000 mL × 0.1 mol/L = 100 mol/mL
Since the molar mass of NaOH is 40.9971 g/mol, we can calculate the mass of NaOH pellets needed:
mass = moles × molar mass
mass = 100 mol/mL × 40.9971 g/mol = 4099.71 g
Therefore, you would need approximately 4099.71 grams of NaOH pellets to prepare 1 liter of 0.1 M NaOH solution.