# chemistry

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At 25 °C only 0.0990 mol of the generic salt AB is soluble in 1.00 L of water. What is the Ksp of the salt at 25 °C?

• chemistry -

.........AB==> A^+ + B^-
I.......solid..0......0
C.......solid..x......x
E.......solid..x......x

Ksp = (A^+)(B^-) = (x)(x)
The problem tell you 0.0990 mol soluble in 1L; therefore M = x = 0.0990/1
Substitute and solve for Ksp.
Note: the salt could be
AB ==> A^2+ + B^2- or
AB ==> A^3+ + B^3-
but none of that will change Ksp.

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