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Pete slides a crate up a ramp at an angle of 25◦ by exerting a 290 N force parallel to the ramp. The crate moves at a constant speed. The coefficient of friction is 0.28.
How much work did Pete do when the crate was raised a vertical distance of 2.24 m?
Answer in units of J

  • physics -

    d = 2.24m/sin25 = 5.30 m Parallel to the

    Work = Fex * d = 290 * 5.30 = 153t J.

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