Aluminium is manufactured by electrolysis(electrolytic decomposition) of bauxite, Al2O3. How much aluminium can be obtained from 1kg of pure bauxite?
--you have 1 mol of Al2O3 n 1 kg....I still don't get it.
I posted a response at the original post.
To determine how much aluminum can be obtained from 1kg of pure bauxite, we need to use the stoichiometry of the reaction and the molar masses of the substances involved.
First, let's write the balanced chemical equation for the electrolysis of bauxite:
2Al2O3(s) → 4Al(s) + 3O2(g)
From the balanced equation, we can see that 2 moles of Al2O3 yield 4 moles of Al. This means that 1 mole of Al2O3 will yield 2 moles of Al.
The molar mass of Al2O3 is 101.96 g/mol. So, 1kg (1000g) of Al2O3 is equal to 1000/101.96 = 9.8 moles of Al2O3.
Since 1 mole of Al2O3 yields 2 moles of Al, we multiply the number of moles of Al2O3 by 2 to find the number of moles of Al:
9.8 moles Al2O3 × 2 = 19.6 moles Al
Finally, we need to convert moles of Al to grams by multiplying by the molar mass of Al, which is 26.98 g/mol:
19.6 moles Al × 26.98 g/mol = 528.8 g of Al
Therefore, from 1kg of pure bauxite, we can obtain approximately 528.8 grams of aluminum.