posted by Gabriella .
How much work is done by the system when
2.00 moles of O2 expand from a volume of
3.00 liters to a volume of 9.6 liters against a constant external pressure of 0.0100 atm
answer in units of joules
w = -pdV
Work done by the system is -
pdV is 0.01*(9.6-6.6)
where did you get the 6.6 from? and i did the work correctly and the answer was wrong.
I typed in the wrong number. That's V2-V1 = (9.6-3.00) so
work = -0.01*6.6 = ? in L*atm since 0.01 is in atm and delta V is L. The problem asks for joules. Convert L*atm to Joules.
1 L*atm = 101.325 joules.
This may be a little late but what about moles