a rubber ball is thrown downwards off a balcony. after it travels 55m it has a speed of 46.5m/s. what is the initial velocity

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thu,10-10-13,7:27 PM.

See previous post: Thu,10-10-13,7:27PM.

thu,10-10-13,7:27 PM.

To find the initial velocity of the rubber ball, we can use the equations of motion for uniform acceleration. The equation that relates distance, initial velocity, final velocity, and acceleration is:

v^2 = u^2 + 2as

Where:
v = final velocity (46.5 m/s)
u = initial velocity (unknown)
s = distance traveled (55 m)
a = acceleration (assuming it is due to gravity, which is approximately 9.8 m/s^2)

From the given information, we can rearrange the equation to solve for the initial velocity:

u^2 = v^2 - 2as

Substituting the given values:

u^2 = (46.5 m/s)^2 - 2(9.8 m/s^2)(55 m)

Simplifying:

u^2 = 2162.25 m^2/s^2 - 1078 m^2/s^2

u^2 = 1084.25 m^2/s^2

Taking the square root of both sides, we find:

u ≈ √1084.25 m^2/s^2

u ≈ 32.9 m/s

Therefore, the initial velocity of the rubber ball is approximately 32.9 m/s.