can some one tell me the simplified cube radical form of (64x^5y^7)^1/3
Hi Roger,
For this problem, you have to cuberoot each of the element (64, x^5 & y^7) separately.
For 64 , cuberoot of 64 is 4.
x^5 , cuberoot is x^(5/3)
y^7, the cuberoot is y^(7/3)
Therefore the simplified cube radical form is 4x^(5/3)y^(7/3)
Hope this helps you
Please don't switch names
I replied to you when you posted this earlier under a different name.
Did you not look at the reply before reposting?
http://www.jiskha.com/display.cgi?id=1381327293
btw, in your posting as Kim, you had x^3 instead of the current x^5
To find the simplified cube radical form of the expression (64x^5y^7)^(1/3), we need to simplify the expression inside the parentheses and then apply the cube root.
First, let's simplify the expression (64x^5y^7):
To evaluate 64^(1/3), we find the cube root of 64, which is 4.
To simplify x^5, we divide the exponent by 3 (since we are taking the cube root): 5/3.
To simplify y^7, we also divide the exponent by 3: 7/3.
So, now our expression becomes: 4 * x^(5/3) * y^(7/3).
Therefore, the simplified cube radical form of (64x^5y^7)^(1/3) is 4x^(5/3)y^(7/3).