how can i graph this scenario

a hawk flies north 5 miles in 5 min. it turns around and flies south 3 miles in 3 min, then turns back around and flies north 2 miles in 2 min.

To graph this scenario, start by setting up a coordinate system. Let's assume that the hawk starts at the origin (0,0) and moves along the y-axis (north and south).

1. First, plot the initial position of the hawk, which is at the origin (0,0).

2. The hawk flies north 5 miles in 5 minutes. Since it moves along the y-axis in the positive direction, plot a point 5 units above the initial position. So, the new position is (0, 5).

3. Next, the hawk turns around and flies south 3 miles in 3 minutes. Since it moves in the negative y-direction (south), plot a point 3 units below the previous position. The new position becomes (0, 5 - 3) = (0, 2).

4. Now, the hawk turns around again and flies north 2 miles in 2 minutes. Again, plot a point 2 units above the previous position. The new position is (0, 2 + 2) = (0, 4).

5. Connect the plotted points in the order they were visited. Start from the origin (0,0) and draw a line to (0, 5), then to (0, 2), and finally to (0, 4).

The resulting graph is a straight vertical line segment connecting the plotted points. The x-coordinate remains constant at 0, indicating that the hawk only moves along the y-axis.

Note: The time periods (5 min, 3 min, 2 min) are not directly reflected in the graph, as it only shows the positions at specific points in time.