Algebra 1 Please, help me!
posted by Anonymous .
Solve 2x  3y = 9 for y.
Solve 2a + ab = c for a.

Solve 2s  k = 11 for k?

3y = 2x + 9
y = 2/3x  3
Try the others now. 
I have but I don't remeber how.

Do it the same way.

To solve any linear equation in x and y for y takes 2 steps
1. move all terms except the y term to the right
3y = 2x + 9
2. divide each term by the coefficient of the y term
y = (2/3)x + 9/3
y = (2/3)x  3 
Can anyone provide the steps of solving these equations? I am truly struggling.

Reiny gave you these steps.

I don't understand what steps must be taken in order to solve the other equations.

I know it is the same process but I an still very confused.

2x  3y = 9
Subtract 2x from both sides. Now, you want this in the form of y = mx + b. So, I will write this as 3y = 2x (since you subtract) + 9 (since we know 9 is positive).
3y = 2x + 9
Now, divide all terms by 3.
y = 2/3x (or 2/3x like Reiny showed)  3 (because 9 / 3 = 3)
y = 2/3x  3 
I already know this. I was referring to the other equations.

2a + ab = c
a (2 + b) = c
Divide both sides by 2+b.
a = c /(2+b)
I'm not sure on the other one.
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