Algebra 1-- Please, help me!

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Solve 2x - 3y = 9 for y.

Solve 2a + ab = c for a.

  • Algebra 1-- Please, help me! -

    Solve 2s - k = 11 for k?

  • Algebra 1-- Please, help me! -

    -3y = -2x + 9

    y = -2/-3x - 3

    Try the others now.

  • Algebra 1-- Please, help me! -

    I have but I don't remeber how.

  • Algebra 1-- Please, help me! -

    Do it the same way.

  • Algebra 1-- Please, help me! -

    To solve any linear equation in x and y for y takes 2 steps
    1. move all terms except the y term to the right
    -3y = -2x + 9

    2. divide each term by the coefficient of the y term

    y = (-2/-3)x + 9/-3
    y = (2/3)x - 3

  • Algebra 1-- Please, help me! -

    Can anyone provide the steps of solving these equations? I am truly struggling.

  • Algebra 1-- Please, help me! -

    Reiny gave you these steps.

  • Algebra 1-- Please, help me! -

    I don't understand what steps must be taken in order to solve the other equations.

  • Algebra 1-- Please, help me! -

    I know it is the same process but I an still very confused.

  • Algebra 1-- Please, help me! -

    2x - 3y = 9

    Subtract 2x from both sides. Now, you want this in the form of y = mx + b. So, I will write this as -3y = -2x (since you subtract) + 9 (since we know 9 is positive).

    -3y = -2x + 9

    Now, divide all terms by -3.

    y = -2/-3x (or 2/3x like Reiny showed) - 3 (because 9 / -3 = -3)

    y = 2/3x - 3

  • Algebra 1-- Please, help me! -

    I already know this. I was referring to the other equations.

  • Algebra 1-- Please, help me! -

    2a + ab = c

    a (2 + b) = c

    Divide both sides by 2+b.

    a = c /(2+b)

    I'm not sure on the other one.

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