# Algebra 1-- Please, help me!

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Solve 2x - 3y = 9 for y.

Solve 2a + ab = c for a.

• Algebra 1-- Please, help me! -

Solve 2s - k = 11 for k?

• Algebra 1-- Please, help me! -

-3y = -2x + 9

y = -2/-3x - 3

Try the others now.

• Algebra 1-- Please, help me! -

I have but I don't remeber how.

• Algebra 1-- Please, help me! -

Do it the same way.

• Algebra 1-- Please, help me! -

To solve any linear equation in x and y for y takes 2 steps
1. move all terms except the y term to the right
-3y = -2x + 9

2. divide each term by the coefficient of the y term

y = (-2/-3)x + 9/-3
y = (2/3)x - 3

• Algebra 1-- Please, help me! -

Can anyone provide the steps of solving these equations? I am truly struggling.

• Algebra 1-- Please, help me! -

Reiny gave you these steps.

• Algebra 1-- Please, help me! -

I don't understand what steps must be taken in order to solve the other equations.

• Algebra 1-- Please, help me! -

I know it is the same process but I an still very confused.

• Algebra 1-- Please, help me! -

2x - 3y = 9

Subtract 2x from both sides. Now, you want this in the form of y = mx + b. So, I will write this as -3y = -2x (since you subtract) + 9 (since we know 9 is positive).

-3y = -2x + 9

Now, divide all terms by -3.

y = -2/-3x (or 2/3x like Reiny showed) - 3 (because 9 / -3 = -3)

y = 2/3x - 3

• Algebra 1-- Please, help me! -

I already know this. I was referring to the other equations.

• Algebra 1-- Please, help me! -

2a + ab = c

a (2 + b) = c

Divide both sides by 2+b.

a = c /(2+b)

I'm not sure on the other one.

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