arthur is riding a horse at a velocity of 4m/s. four seconds after, he is already traveling at a velocity of 12m/s. what is his acceleration
a = (V-Vo)/t
a = (12-4)/4 = 2 m/s^2.
Well, Arthur seems to have quite the need for speed! Let's calculate his acceleration.
Acceleration is defined as the change in velocity divided by the time taken. In this case, we can find the change in velocity by subtracting the initial velocity from the final velocity.
Change in velocity = Final velocity - Initial velocity
Change in velocity = 12 m/s - 4 m/s
Change in velocity = 8 m/s
Now, we can calculate the acceleration by dividing the change in velocity by the time taken:
Acceleration = Change in velocity / Time taken
Acceleration = 8 m/s / 4 s
Acceleration = 2 m/s²
So, Arthur's acceleration is 2 meters per second squared. That's one fast horse he's got there!
To find the acceleration, we can use the formula:
acceleration (a) = change in velocity (Δv) / time (t)
Given that Arthur's initial velocity (u) is 4 m/s and his final velocity (v) is 12 m/s, we can calculate the change in velocity:
Δv = v - u
Δv = 12 m/s - 4 m/s
Δv = 8 m/s
The time (t) is given as 4 seconds.
Now we can substitute the values into the formula to find the acceleration:
a = Δv / t
a = 8 m/s / 4 s
a = 2 m/s^2
Therefore, Arthur's acceleration is 2 m/s^2.
To find the acceleration, we can use the formula:
acceleration (a) = change in velocity (Δv) / time (t)
Given that Arthur's initial velocity (u) is 4 m/s and his final velocity (v) is 12 m/s, we can calculate the change in velocity:
Δv = v - u
= 12 m/s - 4 m/s
= 8 m/s
The time taken (t) is 4 seconds.
Now we can substitute the values into the formula to find the acceleration:
a = Δv / t
= 8 m/s / 4 s
= 2 m/s^2
Therefore, Arthur's acceleration is 2 m/s^2.