A cylindrical tank could hold 100.48m^3 of water. If the height of the tank is 2m, what is the radius of its base?
πr^2 h = 100.48
2π r^2 = 100.48
r^2 = 100.48/(2π) = 15.99188..
r = √ ...
= appr 4.00 m
To find the radius of the base of a cylindrical tank, we can use the formula for the volume of a cylinder:
Volume = π × r^2 × h
where "r" is the radius of the base, "h" is the height of the cylinder, and "π" is a mathematical constant approximately equal to 3.14159.
In this case, we are given that the volume of the tank is 100.48 m^3 and the height is 2 m. We can substitute these values into the formula and solve for the radius.
100.48 = π × r^2 × 2
First, let's rearrange the equation to solve for the radius, "r":
r^2 = 100.48 / (2π)
r^2 ≈ 100.48 / (6.28318)
r^2 ≈ 16
To find the value of "r", we take the square root of both sides:
r ≈ √16
r ≈ 4
Therefore, the radius of the base of the cylindrical tank is approximately 4 meters.