The speed of a moving sidewalk at an airport is 2ft/sec. A person can walk 93ft forward on the moving sidewalk in the same time it takes to walk 12ft on a non moving sidewalk in the oppsite direction. At what rate would a person walk on a nonmoving sidewalk?
T = d/r = 93Ft/2Ft/s = 46.5 s. To ride 93 Ft.
V = d/T = 12Ft/46.5s. = 0.258 Ft./s.
To solve this problem, let's define the variables:
Let's call the rate at which a person walks on a non-moving sidewalk "x" ft/sec.
Given information:
Speed of the moving sidewalk = 2 ft/sec
Distance walked on the moving sidewalk = 93 ft
Distance walked on the non-moving sidewalk in the opposite direction = 12 ft
We can use the equation: Time = Distance / Speed.
For the person walking on the moving sidewalk, the time it takes to walk 93 ft is: Time_moving_sidewalk = Distance_moving_sidewalk / Speed_moving_sidewalk.
Plugging in the given values:
Time_moving_sidewalk = 93 ft / 2 ft/sec = 46.5 sec
For the person walking on the non-moving sidewalk, the time it takes to walk 12 ft is: Time_nonmoving_sidewalk = Distance_nonmoving_sidewalk / Speed_nonmoving_sidewalk.
Plugging in the given values:
Time_nonmoving_sidewalk = 12 ft / x ft/sec = 12/x sec
Since the time taken on both sidewalks is the same, we can set up the following equation:
Time_moving_sidewalk = Time_nonmoving_sidewalk
46.5 sec = 12/x sec
To solve for x, we can cross-multiply and then solve for x:
46.5x = 12
x = 12 / 46.5 ≈ 0.26 ft/sec
Therefore, a person would walk at a rate of approximately 0.26 ft/sec on a non-moving sidewalk.