The speed of a moving sidewalk at an airport is 2ft/sec. A person can walk 93ft forward on the moving sidewalk in the same time it takes to walk 12ft on a non moving sidewalk in the oppsite direction. At what rate would a person walk on a nonmoving sidewalk?

T = d/r = 93Ft/2Ft/s = 46.5 s. To ride 93 Ft.

V = d/T = 12Ft/46.5s. = 0.258 Ft./s.

To solve this problem, let's define the variables:

Let's call the rate at which a person walks on a non-moving sidewalk "x" ft/sec.

Given information:

Speed of the moving sidewalk = 2 ft/sec
Distance walked on the moving sidewalk = 93 ft
Distance walked on the non-moving sidewalk in the opposite direction = 12 ft

We can use the equation: Time = Distance / Speed.

For the person walking on the moving sidewalk, the time it takes to walk 93 ft is: Time_moving_sidewalk = Distance_moving_sidewalk / Speed_moving_sidewalk.

Plugging in the given values:
Time_moving_sidewalk = 93 ft / 2 ft/sec = 46.5 sec

For the person walking on the non-moving sidewalk, the time it takes to walk 12 ft is: Time_nonmoving_sidewalk = Distance_nonmoving_sidewalk / Speed_nonmoving_sidewalk.

Plugging in the given values:
Time_nonmoving_sidewalk = 12 ft / x ft/sec = 12/x sec

Since the time taken on both sidewalks is the same, we can set up the following equation:

Time_moving_sidewalk = Time_nonmoving_sidewalk

46.5 sec = 12/x sec

To solve for x, we can cross-multiply and then solve for x:

46.5x = 12

x = 12 / 46.5 ≈ 0.26 ft/sec

Therefore, a person would walk at a rate of approximately 0.26 ft/sec on a non-moving sidewalk.