posted by anon .
An elevator is stopped at the ground floor. It starts moving upwards at constant acceleration a>0 for 5 seconds. It then keeps a constant speed for 35 seconds. Finally, it slows down with an acceleration of the same magnitude (but opposite direction) −a , until it comes to a halt at the top floor. The top floor is 320 meters above the ground floor.
(a) What is the maximal speed v of the elevator ? (in m/s)
(b) What is the acceleration a ? (in m/s2)
did you got all the answers?
to solve its the distance traveled/ 40(this is velocity)
for acceleration its the velocity/5
thnx dude...........and what other questions did you got?
How did you get the velocity 40 ?
I mean how did you get it d/40* ?
speed = distance /time
and time is 35+5=40.