A toy car runs off the edge of a table that is 1.150 m high. The car lands 0.380 m from the base of the table. It takes 0.48 s for it to fall.How fast was the car going on the table? ______m/s
in the horizonal distance,
distance=speed*time
speed=.380/.48 m/s Your teacher is too easy.
To find the speed of the car on the table, we can use the laws of physics and the concept of conservation of energy.
First, let's determine the initial vertical velocity of the car as it falls off the table. We can use the equation:
v = u + gt
Where:
v = final velocity (0 m/s, as the car hits the ground and stops)
u = initial velocity (the speed on the table)
g = acceleration due to gravity (9.8 m/s^2)
t = time (0.48 s)
Rearranging the equation to solve for u:
u = (v - gt)
Substituting the values:
u = (0 - (9.8 * 0.48))
u = -4.704 m/s
(Note: We take negative value for the initial velocity because it's downward.)
Now, let's find the time it takes for the car to reach the ground from the edge of the table. We can use the equation for vertical displacement:
s = ut + (1/2)gt^2
Where:
s = vertical displacement (1.150 m, the height of the table)
u = initial velocity (the speed on the table)
g = acceleration due to gravity (9.8 m/s^2)
t = time (unknown)
Rearranging the equation:
t = sqrt((2s) / g)
Substituting the values:
t = sqrt((2 * 1.150) / 9.8)
t = 0.483 s
Now that we know the time it took for the car to fall from the table, we can find the horizontal velocity using the equation:
v = d / t
Where:
v = velocity (unknown)
d = horizontal distance traveled (0.380 m)
t = time (0.483 s)
Substituting the values:
v = 0.380 / 0.483
v = 0.786 m/s
Therefore, the speed of the car on the table is approximately 0.786 m/s.