identify the vertex and the axis of symmetry of the graph for the function y=3(x+2)^2
a.vertex(2,-3
axis of symmetry x=2
b.vertex(-2,-3)
axis of symmetry x=-2
c.vertex(2,3)
axis of symmetry x=2
d.vertex(-2,3)
axis of symmetry x=-2
identify the maximum or minimum value and the domain and range of the graph of the function y=2(x-3)^2-4.
a.minimum value -4
domain all real numbers
range all real numbers_>_-4
b.max value 4
domain all real numbers
range all real numbers_<_4
c. max value -4
domain all real numbers_<_-4
range all real numbers
d. minimum value 4
domain all real numbers_>_4
range all real numbers
please i need some help guys thanks
1.A
2.D
3.B
4.A
5.A
6.B
maddie is 100% correct
Maddie is 100% correct
1. A
2. D
3. B. Vertex: (-2,-3);
axis of symmetry: x=-2
4. A. Minimum value: -4
domain: all real numbers
5. A. y=-3/50(x-50)^2 +150
6. B. y=4(x-5)^2-3
identify the vertex and the axis of symmetry of the graph for the function y=3(x+2)^2
vertex at (-2,0)
axis: x = -2
Looks like a typo or a bad set of answers
If it was y = 3 + (x+2)^2
then the vertex is at (-2,3)
identify the maximum or minimum value and the domain and range of the graph of the function y=2(x-3)^2-4.
vertex at (3,-4)
axis: x=3
minimum at vertex: y = -4
domain all reals
range: all reals >= -4 (where the vertex is)
if you know that
y = a(x-h)^2 + k
has axis of symmetry at x=h
and vertex at (h,k)
all polynomials have domain of all reals numbers
you are home free.