# URGENT ALGEBRA 2

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identify the vertex and the axis of symmetry of the graph for the function y=3(x+2)^2
a.vertex(2,-3
axis of symmetry x=2
b.vertex(-2,-3)
axis of symmetry x=-2
c.vertex(2,3)
axis of symmetry x=2
d.vertex(-2,3)
axis of symmetry x=-2

identify the maximum or minimum value and the domain and range of the graph of the function y=2(x-3)^2-4.
a.minimum value -4
domain all real numbers
range all real numbers_>_-4
b.max value 4
domain all real numbers
range all real numbers_<_4
c. max value -4
domain all real numbers_<_-4
range all real numbers
d. minimum value 4
domain all real numbers_>_4
range all real numbers

please i need some help guys thanks

• URGENT ALGEBRA 2 -

if you know that

y = a(x-h)^2 + k

has axis of symmetry at x=h
and vertex at (h,k)

all polynomials have domain of all reals numbers

you are home free.

• URGENT ALGEBRA 2 -

• URGENT ALGEBRA 2 -

im not sure steve should be able to give you the answer im stumped on this one to ray

• URGENT ALGEBRA 2 -

identify the vertex and the axis of symmetry of the graph for the function y=3(x+2)^2

vertex at (-2,0)
axis: x = -2
If it was y = 3 + (x+2)^2
then the vertex is at (-2,3)

identify the maximum or minimum value and the domain and range of the graph of the function y=2(x-3)^2-4.
vertex at (3,-4)
axis: x=3
minimum at vertex: y = -4
domain all reals
range: all reals >= -4 (where the vertex is)

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