How to differ AgBr from AgI? which is suitable for that among these...? Dil HNO3,Dil HCl,Dil H2SO4,Conc HNO3,Conc Cl3CCOOH

specifically this is qualitative chem. The two compounds are metal halides and the common condition which the test is proceeded is in acidic condition. The most suitable reagent for that is dil nitric acid.

The reagent to use is HNO3 but that doesn't dissolve either. AgCl is soluble in NH3 whereas AgI is almost insoluble.

To differentiate between AgBr (silver bromide) and AgI (silver iodide), you can use the following steps:

1. Prepare a small amount of each compound: AgBr and AgI.

2. Start with Dil HNO3 (dilute nitric acid). Dilute HNO3 reacts with AgBr producing a yellowish color and AgI remains unchanged. Therefore, AgBr will show a color change when treated with dilute HNO3, while AgI will not.

3. Next, try Dil HCl (dilute hydrochloric acid). Dilute HCl reacts with AgBr producing a white precipitate of AgCl, while AgI remains unchanged. This means that AgBr will produce a white precipitate when treated with dilute HCl, whereas AgI will not.

4. Move on to Dil H2SO4 (dilute sulfuric acid). Dilute H2SO4 does not react with either AgBr or AgI. So there will be no color change or precipitate formation when either compound is treated with dilute H2SO4.

5. Use Conc HNO3 (concentrated nitric acid). Conc HNO3 reacts with both AgBr and AgI, producing the respective nitrate salts (AgBr forms AgNO3 and AgI forms AgNO3). This means that neither compound will show any distinct difference when treated with concentrated nitric acid alone.

6. Finally, try Conc Cl3CCOOH (concentrated acetic acid). This reagent does not react significantly with AgBr or AgI. Therefore, both compounds will remain unchanged when treated with concentrated acetic acid.

Based on these observations, you can conclude that Dil HNO3 and Dil HCl are suitable for distinguishing between AgBr and AgI. Dil HNO3 will produce a color change with AgBr, while Dil HCl will produce a precipitate with AgBr. AgI, on the other hand, will remain unchanged in both cases.