Rounded to the nearest ten I am 780. I am even. The sum of my digits is 17. How do you get the answer?
Here are possibilities:
775, 776, 777, 778, 779, 780, 781, 782, 783, 784
Which digits add up to 17?
I'm not sure. I need help figuring it out. I know the answer is 782, but I don't know how it is solved.
I got it!!! 7+2+8=17. Which gives me the even number 782 and when round to the nearest tenth gives me 780!! Oh good ness, thank you! :)
Yay!!!! You got it! :-)
You're very welcome, gigi.
To find the number that satisfies all the given conditions, we'll break down the problem step by step.
1. Rounded to the nearest ten, the number is 780.
This means the number lies between 775 and 784 since both are equally close to 780. We need to find the number within this range that satisfies the other given conditions.
2. The number is even.
From the range we found in step 1, we can eliminate the odd numbers in that range. So, we are left with two possible numbers: 776 and 780.
3. The sum of the digits is 17.
To check if the number is 776 or 780, we need to add up the digits of both numbers and see if they sum up to 17. Let's do the calculation:
- For 776: 7 + 7 + 6 = 20
- For 780: 7 + 8 + 0 = 15
So, only the number 776 has digits that sum up to 17.
Therefore, the number that satisfies all the given conditions is 776.