A triangle has a perimeter of 81 inches. The side lengths can be found by x, 3x-1, and 4x+2
what is the value of x?
81 = x + 3x - 1 + 4x + 2
81 = 8x + 1
80 = 8x
10 = x
x + 3x-1 + 4x +2 = 81
8x+ 1 = 81
8x+1-1 = 81-1
8x = 80
8x/8 = 80/8
x = 10
10
To find the value of x, we need to use the fact that the perimeter of the triangle is equal to the sum of the lengths of its sides.
The perimeter of a triangle with side lengths x, 3x - 1, and 4x + 2 is given as 81 inches. Let's write an equation using this information:
Perimeter = x + (3x - 1) + (4x + 2)
Now, we can simplify the equation by combining like terms:
81 = x + (3x - 1) + (4x + 2)
81 = x + 3x - 1 + 4x + 2
Next, we will combine the terms:
81 = 8x + 1
To solve for x, we will isolate x on one side of the equation. We can do this by subtracting 1 from both sides:
81 - 1 = 8x + 1 - 1
80 = 8x
Finally, we will divide both sides by 8 to get the value of x:
80/8 = 8x/8
10 = x
Therefore, the value of x is 10.