(Radical 15- radical 5) (radical 15 + radical 5) and radical (-20) squared /2
Second ones answer is 10 what about 1st? 1? 0?
If I read the first one correctly ...
(√15 -√5)(√15 + √5)
= 15 + √5√15 - √5√15 - 5
= 10
If the second one is (√-20)^2 / 2
= -20/2
= -10
long way:
(√-20)^2 / 2
= (1/2) √-20 * √-20
= (1/2) i√20 * i√20
= (1/2) (20)(i^2) , but i^2 = -1
= (1/2)(20)(-1)
= -10
To simplify the expressions, let's break them down step-by-step.
Expression 1: (Radical 15 - Radical 5) * (Radical 15 + Radical 5)
To simplify this expression, we can use the formula (a - b) * (a + b) = a^2 - b^2.
Let's assign Radical 15 as "a" and Radical 5 as "b".
Substituting the values into the formula, we have (Radical 15 - Radical 5) * (Radical 15 + Radical 5) = (Radical 15)^2 - (Radical 5)^2.
Simplifying further, we get (15 - 5) = 10.
Therefore, the value of the expression (Radical 15 - Radical 5) * (Radical 15 + Radical 5) is 10.
Expression 2: Radical (-20)^2 / 2
To simplify this expression, we square -20 first.
(-20)^2 = 400
Then, find the square root of 400.
√400 = 20
Finally, we divide 20 by 2.
20 / 2 = 10
Therefore, the value of the expression Radical (-20)^2 / 2 is 10.