if 96g so2 is added to 2 moles of oxygen at stp, what is the mass of so3 that is formed
2SO2 + O2 ==> 2SO3
mols SO2 = g/molar mass = ?
Using the coefficients in the balanced equation, convert mols SO2 to mols SO3.
Now convert mols SO3 to g. g = mols x molar mass.
n=m/M
=m.M
=80g.mol.1,5mol
=120g
To determine the mass of SO3 that is formed when 96g of SO2 is added to 2 moles of oxygen at STP, we need to use the balanced chemical equation for the reaction between SO2 and O2 to form SO3.
The balanced chemical equation is:
2SO2 + O2 -> 2SO3
From the equation, we can see that 2 moles of SO2 react with 1 mole of O2 to produce 2 moles of SO3.
First, let's convert the given mass of SO2 to moles using its molar mass.
The molar mass of SO2 is calculated as follows:
S: 1 atom x 32.07 g/mol = 32.07 g/mol
O: 2 atoms x 16.00 g/mol = 32.00 g/mol
Total molar mass = 32.07 g/mol + 32.00 g/mol = 64.07 g/mol
Number of moles of SO2 = Mass of SO2 / Molar mass of SO2 = 96 g / 64.07 g/mol
Now, we have the number of moles of SO2 as 1.50 moles (rounded to two decimal places).
Since the reaction ratio is 2:1 for SO2 to O2, we have 1.50 moles of SO2 reacting with half the number of moles of O2, which is 0.75 moles.
Now, the reaction ratio for SO2 to SO3 is 2:2, so the number of moles of SO3 produced is the same as the number of moles of SO2, which is 1.50 moles.
Finally, to calculate the mass of SO3 produced, we multiply the number of moles of SO3 by its molar mass.
The molar mass of SO3 is calculated as follows:
S: 1 atom x 32.07 g/mol = 32.07 g/mol
O: 3 atoms x 16.00 g/mol = 48.00 g/mol
Total molar mass = 32.07 g/mol + 48.00 g/mol = 80.07 g/mol
Mass of SO3 = Number of moles of SO3 x Molar mass of SO3 = 1.50 moles x 80.07 g/mol
Therefore, the mass of SO3 that is formed is 120.11 grams.