# Dma 040

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v =1/3ah, solve for h

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what is the total molar concentration of all the ions in .040 M solutions of the following salts in water?
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v=1/3ah solve for h
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Determination of Kf of Cu(NH3)4 (aq) with given 10mL of 6M NH3 mix with 40mL of 1M Cu. This is what I have so far: nCu= .040L x 1= .040mol nNH3= .010L x 6= .060mol Cu^2+ + 4NH3 -> Cu(NH3)4 .040 .06 0 -.040 4(-.040) +.040 0 -.1 .040 …

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