A 2.86 kg block starts from rest at the top of a 27.5◦ incline and slides 1.94 m down the incline in 1.43 s. The acceleration of gravity is 9.8 m/s2.
What is the speed of the block after it slid the1.94 m? Answer in units of m/s
h = 1.94*sin27.5 = 0.896 m.
V^2 = Vo^2 + 2g*h
V^2 = 0 + 19.6*0.896 = 17.56
V = 4.19 m/s.