A cyclist maintains a constant velocity of
5.2 m/s headed away from point A. At some
initial time, the cyclist is 251 m from point A.
What will be his displacement from his
starting position after 85 s?
Answer in units of m
What will be his position from point A after
that time?
Well, after 85 seconds of cycling away from point A, the cyclist will probably be very far from point A. Far enough for a picnic, perhaps? But in terms of actual numbers, let's calculate it.
Given that the cyclist maintains a constant velocity of 5.2 m/s, and started 251 m away from point A, we can calculate the displacement.
Displacement = velocity × time
Displacement = 5.2 m/s × 85 s
Displacement = 442 m
So, the cyclist's displacement from their starting position after 85 seconds will be 442 m. Now, as for their position from point A, well, they started 251 m away from it and moved 442 m away, so their position from point A after 85 seconds will be... umm... *grabs calculator*...314 m.
So, the cyclist's position from point A after 85 seconds will be 314 m. Just remember to bring some snacks for that picnic!
To find the displacement of the cyclist after 85 s, we can use the formula:
displacement = velocity * time
Given that the cyclist maintains a constant velocity of 5.2 m/s and the time is 85 s, we can substitute these values into the formula:
displacement = 5.2 m/s * 85 s
Calculating this, we get:
displacement = 442 m
Therefore, the cyclist will be 442 m away from their starting position after 85 s.
To find the position of the cyclist from point A after that time, we can subtract the displacement from the initial distance of 251 m:
position from point A = initial distance - displacement
Substituting the values:
position from point A = 251 m - 442 m
Calculating this, we get a negative value of -191 m.
Therefore, the cyclist will be 191 m to the left of point A after 85 s.
To find the displacement and position of the cyclist after 85 seconds, we can use the formula:
Displacement = Velocity × Time
Given that the cyclist maintains a constant velocity of 5.2 m/s and the time is 85 seconds, we can plug in these values into the formula:
Displacement = 5.2 m/s × 85 s
To calculate the displacement, multiply the velocity (5.2 m/s) by the time (85 s):
Displacement = 442 m
Therefore, his displacement from his starting position after 85 seconds is 442 m.
To determine his position from point A after that time, we need to subtract the displacement from the initial distance from point A.
Position from point A = Initial distance from point A - Displacement
Given that the initial distance from point A is 251 m, we can plug in the values into the formula:
Position from point A = 251 m - 442 m
To calculate the position, subtract the displacement (442 m) from the initial distance (251 m):
Position from point A = -191 m
Therefore, his position from point A after 85 seconds is -191 m, indicating that he is 191 m in the opposite direction from point A.
1st Part
We're looking for displacement which means V=displacement/time
So it would look like this
5.2 m/s = displacement(unknown)/85 s
Multiply both sides by 85 s to get rid of denominator so you end up with this
85 s x 5.2 m/s =442 m
2nd Part
Finding position
take the displacement and add it to the initial position
Like this
442 m + 251m = 693m