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How many mL of 0.416 M of HCl are needed to dissolve 8.68 g of BaCO3?
2HCl(aq)+BaCO3(s)=BaCl2(aq)+H2O(l)+CO2(g)

  • chemistry -

    BaCO3 + 2HCl ==> H2O + CO2 + BaCl2

    mols CaCO3 = grams/molar mass = ?
    mols HCl = 2x that. (Look at the coefficients in the balanced equation.)
    M HCl = mols HCl/L HCl You have mols and M, solve for L HCl and convert to mL.

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